Inductance Calculator - Air Core, Toroid and AL Value Coils

    Find the inductance of an air-core coil, a toroid or any core with an AL value, or the turns to wind for a target, using Wheeler's formula instead of the ideal solenoid.

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    Inductance or turns

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    Coil inductance for three constructions on one page

    Three kinds of coil, each with the formula that actually fits it: a single-layer air-core coil through Wheeler's formula, a toroid through its dimensions and the core's relative permeability, and any core whose maker prints an AL value. The calculator finds the inductance from the number of turns or the turns for a target inductance. 100 turns on a 20 mm form, 50 mm long, give 67.57 µH; the textbook long-solenoid formula would say 78.96 µH.

    double the turns, four times the inductance
    0.357
    Wheeler ÷ ideal for a coil as long as a quarter of its diameter
    2,000×
    a ferrite toroid with µr 2,000 against the same toroid in air

    What the form asks, coil by coil

    1. Kind of coil - air-core coil (wire wound on a plastic form or on nothing), toroid with a known permeability, or a core with an AL value from its datasheet.
    2. What to find - the inductance from the turns, or the turns for a target inductance.
    3. Turns, or the target and its unit - turns may be fractional on an air coil; the target can be in nH, µH, mH or H.
    4. Size unit - millimeters or inches, for the air coil and the toroid.
    5. Dimensions - for an air coil its outside diameter and winding length; for a toroid the inner and outer diameter and the height.
    6. Relative permeability - toroid only. 1 for air or plastic, the datasheet's initial permeability for a magnetic core.
    7. AL value - AL cores only, in nH per turn squared, as printed by the core maker.
    8. Read the result - the inductance or the turns to wind, the equivalent AL, and a table of the same coil with other turn counts.

    Why turns count twice and a core counts only when it is closed

    Every turn adds to the magnetic flux, and the same flux then passes through every turn. That is the whole reason inductance grows with : 20 turns on a core with an AL of 250 nH give 100 µH, and 40 turns give 400 µH, not 200.

    The formula most people learn first, L = µ0N²A ÷ l, assumes a coil so long that the field inside is uniform and the ends do not matter. Wikipedia's table of inductance formulas carries it with a correction factor, the Nagaoka coefficient, which is close to 1 only for a coil much longer than its diameter. For ordinary proportions the same table gives Wheeler's approximation, L = r²N² ÷ (23r + 25l) in microhenries with the radius and length in centimeters, valid when the length is at least a fifth of the diameter. A 10 mm by 200 mm coil lands within 1% of the ideal value (ratio 0.99); a 20 mm coil only 5 mm long reaches just 0.357 of it.

    Magnetic cores are where most online coil calculators go wrong. Wikipedia's inductor article describes a coil on a straight rod: the field lines leaving one end have to return through the air to the other, which reduces the field, and a closed magnetic circuit, typically a toroid, is what gives the higher inductance. Multiplying a rod-wound solenoid by a ferrite's full permeability of 2,000 therefore overstates it badly. This calculator applies the material permeability only to a closed toroid, and for everything else, rods, E-cores, pot cores and gapped cores, it uses the AL value the manufacturer measured on that exact shape.

    A toroid of rectangular cross-section follows L = 2N²h ln(d2 ÷ d1) in nanohenries with the height and diameters in centimeters, the air-core form given in the same table. With a core filling the ring, the inductance is that figure times the relative permeability, and the product µr × 2h ln(d2 ÷ d1) is exactly the toroid's equivalent AL.

    Permeability of core materials, from air to Metglas

    Figures from Wikipedia's permeability table, which warns that the permeability of ferromagnetic materials varies greatly with field strength, composition and fabrication. Ranges are what the table gives, and the maximum values are measured at the stated field.

    Material Relative permeability Condition or frequency
    Air1.00000037treat as 1
    Cobalt nickel zinc ferrite40-125about 2-150 MHz
    Sendust (Al-Si-Fe powder)14-160powder core
    Nickel iron powder14-160about 50 Hz-2 MHz
    Molypermalloy powder (MPP)14-550about 50 Hz-3 MHz
    Nickel zinc ferrite10-2,300about 1 kHz-400 MHz
    Manganese zinc ferrite350-20,000about 100 Hz-4 MHz
    Iron, 99.8% pure5,000maximum
    Electrical steel2,000-38,000at 0.002 T and at 1 T
    Mu-metal20,000-50,00020,000 at 0.002 T
    Nanocrystalline (NANOPERM)80,000at 0.5 T, 10 kHz
    Permalloy100,000at 0.002 T
    Metglas 2714A, annealed1,000,000at 0.5 T, 100 kHz

    The ranges are wide on purpose. Two ferrites both called "MnZn" can differ by a factor of fifty, which is why the permeability field has no preset list: the number belongs on the datasheet of the core in your hand.

    Eleven coils run through the calculator

    Each row is a real input set typed into the form; the result column is what the calculator returns.

    Coil Input Result Note
    Air coil100 turns, 20 × 50 mm67.57 µHideal 78.96 µH, ratio 0.856
    Short air coil10 turns, 20 × 5 mm2.817 µHideal 7.896 µH, ratio 0.357
    Long air coil200 turns, 10 × 200 mm19.55 µHideal 19.74 µH, ratio 0.99
    Air coil in inches50 turns, 1 × 2 in25.81 µHideal 31.34 µH
    Ferrite toroid10 turns, 15/25/10 mm, µr 2,000204.3 µHequivalent AL 2,043 nH
    Same ring in air10 turns, 15/25/10 mm, µr 1102.2 nHAL 1.022 nH
    Powder toroid30 turns, 15/25/10 mm, µr 7568.96 µHAL 76.62 nH
    AL core20 turns, AL 250 nH100 µH40 turns: 400 µH
    Turns for 100 µH, air20 × 50 mm form122 turnsexactly 121.66; 122 give 100.6 µH
    Turns for 1 mH, toroid15/25/10 mm, µr 2,00023 turns23 give 1.081 mH, 22 give 989 µH
    Turns for 47 µH, AL coreAL 100 nH22 turns22 give 48.4 µH, 21 give 44.1 µH

    Patterns hidden in those rows

    Length hurts less than shortness. Going from 50 mm to 5 mm on the same 20 mm form multiplies the ideal formula by ten but the real inductance of 10 turns only goes from 0.6757 µH to 2.817 µH. Squeezing turns together helps, just much less than µ0N²A ÷ l promises.
    The ring shape matters through a logarithm. A toroid's inductance depends on ln(d2 ÷ d1), so doubling the outer diameter of a thin ring does far less than doubling its height. The 15/25 mm ring has ln(1.6667) = 0.511; the height enters directly.
    One more turn is a bigger step on a small coil. At 22 turns the next turn adds about 9% (989 µH to 1.081 mH); at 122 turns it adds under 2%. That is why the turns table under the result shows the neighbors of the suggested count.
    AL hides the geometry, which is the point. A maker's AL includes the core shape, any air gap and the material at low field, which no formula from dimensions can do for an E-core or a gapped pot core. Enter it and the only thing left to guess is the tolerance.

    Reading the numbers you get back

    What you see What it means
    Wheeler ÷ ideal above 0.9long coil, the textbook formula is nearly right
    Wheeler ÷ ideal between 0.5 and 0.9ordinary proportions, the ideal formula overstates by 11-100%
    Warning about a fifth of the diameteroutside the formula's range, treat the figure as rough
    Equivalent AL of a toroidcompare it with the datasheet AL; a large gap means the permeability you typed is not the one the core has
    Suggested turns and the two values beside itpick the side of the target your circuit tolerates; the exact count is rarely a whole number

    All results are small-signal values. Core permeability falls toward saturation at high current, and the measured inductance of a finished coil also depends on how tightly and evenly it is wound.

    Coil questions answered from the formulas

    How do I calculate the inductance of an air-core coil?
    With Wheeler's formula, L (µH) = r²N² ÷ (23r + 25l), radius and length in centimeters. 100 turns with r = 1 cm and l = 5 cm: 10,000 ÷ 148 = 67.57 µH.
    What is an AL value and where do I find it?
    The inductance a core gives per turn squared, in nH. It is printed on the core's datasheet; with it, L = AL × N², so 20 turns on AL 250 nH give 100 µH.
    How many turns do I need for a given inductance?
    N = √(L ÷ AL) for any core with an AL. For 47 µH on AL 100 nH: √470 = 21.68, so 22 turns for 48.4 µH. Choose "turns" in the form and it does the same for air coils and toroids.
    Why doesn't this calculator multiply a rod core by its permeability?
    Because the flux of a rod-wound coil returns through air, so the core cannot raise the inductance by its full material permeability. A closed toroid can, which is why permeability is asked for only there.
    Does inductance go up with the square of the turns on every core?
    In all three formulas here, yes: doubling 50 turns to 100 on the air coil takes 16.89 µH to 67.57 µH. In practice extra turns on an air coil also lengthen it, which pulls the gain a little under four times.
    What permeability should I type for a ferrite toroid?
    The initial permeability from its datasheet. Wikipedia lists manganese zinc ferrites from 350 to 20,000 and nickel zinc from 10 to 2,300, so a guess from the material name alone can be off by more than ten times.
    Can I type the size in inches?
    Yes, switch the size unit. 50 turns on a 1 in form, 2 in long, give 25.81 µH.

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