Poisson Distribution Calculator - Exactly, At Most, At Least

    Exactly k, at most k, at least k or between a and b events when all you know is the average rate λ, with the whole Poisson distribution table and the mean, SD and most likely count.

    Parameters

    Enter data for calculations

    "At least one" means at least 1

    Per period, decimals allowed

    Leave empty for 1 period

    A whole number from 0

    Form progress0 / 3 fields

    💡 Fill in all required fields to unlock the calculate button

    Poisson probabilities from nothing but an average

    How likely are exactly 6 calls in the next hour when a help line averages 4 an hour? The Poisson distribution puts it at 10.42%, and this calculator returns that number together with the "at most" and "at least" versions, a range from a to b and a table of the whole distribution. Two inputs are enough: the average count λ for one period and the count k you are asking about. When the average is per hour and the question covers three hours, enter the number of periods and λ is scaled for you.

    Using the Poisson calculator, field by field

    1. Which probability - exactly k, at most k, at least k, or between a and b inclusive. "None at all" is exactly 0, "at least one" is at least 1.
    2. Average number of events λ - the mean count in one period or area, such as 2.7 goals per game or 0.5 typos per page. Decimals are fine, typed with a dot.
    3. Number of periods - optional. The average is per page and you ask about a 10-page chapter? Enter 10 and λ grows to 5.
    4. Number of events k (and the upper bound b for a range) - always a whole number, because events are counted, not measured.
    5. Read the result - a large tile with the answer to your question, six smaller tiles with the related probabilities, the mean, the standard deviation and the most likely count, and a distribution table with your k highlighted.

    The formula, and three problems worked to the end

    The probability mass function in the NIST/SEMATECH e-Handbook of Statistical Methods is P(X = k) = λk e-λ / k! for k = 0, 1, 2 and so on. "At most k" adds the bars from 0 to k, "at least k" is 1 minus the sum up to k - 1, and both the mean and the variance equal λ. The calculator works with logarithms of the factorials, so it keeps full precision up to λ = 1,000, where a handheld calculator already overflows on 1000!.

    1
    Help line, exactly 6 calls at λ = 4. 46 = 4,096, e-4 = 0.018316, 6! = 720. Result: 4,096 × 0.018316 / 720 = 0.1042, which is 10.42%. A completely quiet hour has only 1.832%, about once in 55 hours.
    2
    A game with an assumed average of 2.7 goals, at least 3 goals. Work through the complement: P(0) = 6.721%, P(1) = 18.15%, P(2) = 24.50%, together 49.36%. At least three goals: 100% - 49.36% = 50.64%. The single most likely score is 2 goals.
    3
    Typos: 0.5 per page, a 10-page chapter, at most 2. λ = 0.5 × 10 = 5. P(X ≤ 2) = e-5 × (1 + 5 + 12.5) = 0.0067379 × 18.5 = 0.1247, or 12.47%. It is the same figure Microsoft gives for =POISSON.DIST(2, 5, TRUE): 0.124652. FALSE in the last argument returns the single bar, exactly 2, which is 0.084224.

    Poisson or binomial? A side-by-side comparison

    Both distributions count events, but they answer different questions. The binomial needs a known number of trials and a probability per trial. The Poisson needs only the average over a period, with no trials to count.

    Feature Poisson Binomial Pick it when
    Inputsaverage λ per periodtrials n and probability pyou only know an average: Poisson
    Largest possible kno upper limitnthe count is capped by the trials: binomial
    Meanλn × p-
    Varianceλ, equal to the meann × p × (1 - p), below the meanvariance far above the mean: neither fits well
    Typical usecalls per hour, goals per game, typos per page, failures per monthhits in 10 shots, defects in a batch of 50, correct answers on a quizevents "over time": Poisson; "per trial": binomial

    With many trials and a small p the two give almost the same answer, so a Poisson with λ = n × p can stand in for the binomial. The NIST e-Handbook gives the rule of thumb: n of at least 20 and p of at most 0.05, with an excellent approximation when n is 100 or more and n × p is at most 10. Its own check uses n = 200 and p = 0.025: exactly 3 successes come to 0.1399995 under the binomial and 0.1403739 under the Poisson with λ = 5.

    The table below repeats that check for a batch of 100 items, each defective with probability 2%. No difference exceeds three tenths of a percentage point.

    Defective items k Binomial (exact) Poisson λ = 2 Difference
    013.26%13.53%+0.27
    127.07%27.07%0.00
    227.34%27.07%-0.27
    318.23%18.04%-0.18
    49.02%9.02%0.00
    53.53%3.61%+0.07
    61.14%1.20%+0.06

    Poisson probability between two numbers

    A range question needs two cumulative sums and a subtraction, which is where hand calculations usually slip by one. At λ = 3, "from 2 to 5 events" is P(X ≤ 5) - P(X ≤ 1) = 91.61% - 19.91% = 71.69%. Note the 1, not the 2: the lower bound itself belongs to the range, so the sum that is taken away stops one step below it. The calculator does this for you when you choose "from a to b", and the table under the result highlights every bar inside the range.

    The same idea covers planning questions. A help line that averages 4 calls an hour sees λ = 32 over an 8-hour shift. A shift with at most 25 calls happens 12.28% of the time, and one with 40 or more 9.560% of the time, so roughly one shift in ten needs extra hands.

    Where Poisson answers go wrong

    An average from the wrong period. λ = 4 per hour is not the average for an 8-hour shift. A question about the shift needs λ = 32. Safer: enter the average per unit and the number of periods, and let the calculator multiply.
    "At least" read as "exactly". At λ = 4, exactly 7 calls is about 5.95%, while at least 7 is 11.07%. "Will 7 or more come in" is always a tail, never a single bar.
    Events that arrive in clusters. Customers who walk into a store as whole families, or outages caused by one storm, are not independent. The model then understates the chance of a very large count.
    No look at the variance. In a Poisson distribution the variance equals the mean. If your data show a mean of 3 and a variance of 9, they are more spread out than the model assumes, and the tail probabilities will come out too optimistic.

    Poisson distribution questions

    What does λ mean in the Poisson distribution?
    The average number of events in the chosen period or area. It is both the expected value and the variance, so at λ = 9 the standard deviation is 3.
    Which count is the most likely?
    The whole-number part of λ, as the NIST e-Handbook states. At λ = 2.7 it is 2. When λ is a whole number there are two equally likely counts: at λ = 6 both 5 and 6 have 16.06% each.
    How do I find the probability of at least one event?
    Choose "at least" and k = 1. It equals 1 - e-λ: at λ = 0.5 that is 39.35%, because zero events has 60.65%.
    Why can λ be a decimal when k cannot?
    An average can be 0.3 events a day, but on any single day the event happened 0, 1, 2 or more times, never 0.3 times. That is why k takes whole numbers only and the distribution is discrete.
    How is the Poisson distribution related to waiting times?
    If the number of events in a period follows a Poisson distribution, the time between consecutive events follows an exponential distribution with mean 1/λ. At 4 calls an hour the gap averages 15 minutes.
    Why does the result sometimes show a power of ten?
    Probabilities below 0.0001 would show only zeros as a percentage. At λ = 2 the chance of 12 or more events is 1.36 × 10⁻⁶, about 1.4 in a million.

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