What is the R-value of 5 inches of fiberglass?

    A bare brick wall leaks 1,175 W and the same wall under 15 cm of wool leaks 169. Get the heat flow, the R-value in both unit systems and what one more layer would buy.

    5 inches of fiberglass batt carries a resistance that follows straight from one number: the conductivity of the material, about 0.044 watts per meter per kelvin, which works out at roughly R-3.3 per inch. Multiply that by the depth and you have the R-value of the layer itself, before anything else in the wall is counted.

    The figure below adds the two films of still air that cling to the faces of any real surface, worth about R-1 together, because that is how building codes define the number they ask you to hit. US codes commonly want R-13 to R-21 in a wall and R-38 to R-60 in an attic, depending on climate zone, so 5 inches of batt lands somewhere specific on that scale rather than being simply good or bad.

    Watts and BTU per hour on the page are worked out for 100 square feet with 70 degrees inside and 10 outside, which is a cold winter day rather than an average one. Change any of those and the heat flow changes with them; the R-value does not, because resistance is a property of the layer and not of the weather crossing it. The comparison table shows what the same depth would give in foam, mineral wool and the masonry it might be sitting against.

    Parameters

    Enter data for calculations

    Figures in brackets are conductivity in W/(m K)

    The depth heat has to cross, not the width of the wall

    Millimeters suit glazing, inches suit US framing

    Only the surface made of the material above

    Square meters or square feet

    Applies to both readings below

    Rsi 0.13 and Rse 0.04, worth R-0.97 together

    Turns the answer into a before and after

    Same choices as the layer above

    Form progress0 / 7 fields

    💡 Fill in all required fields to unlock the calculate button

    One wall, one afternoon of work, and the difference in watts

    A 30 m2 wall of solid brick, 38 cm thick, with 21 °C inside and -5 outside, is losing 1,175.6 W without stopping. Put 15 cm of mineral wool on the outside of it and the same wall loses 169.2 W. Everything else is identical: same bricks, same weather, same house.

    Before, brick alone

    1,175.6 W

    R-3.8 in total, and R-1.0 of that is the two films of still air clinging to the faces. The brick itself contributes R-2.8 across nearly half a meter of masonry.

    After, plus 15 cm of wool

    169.2 W

    R-26.2 in total. The wool alone is worth R-22.4, eight times what the brick was doing, from a layer a little over a third of its thickness.

    That is 1,006.4 W saved, 85.6 percent of the original loss, and 24.2 kWh over a day at that temperature difference. The calculator produces both figures from the same four inputs: what the wall is made of, how thick it is, how big it is and how cold it is outside. Add a second layer and it prints the before, the after and the difference side by side.

    How the number is built, layer by layer

    1. Every layer becomes a resistance. R = thickness divided by conductivity. Fifteen centimeters of mineral wool at 0.038 W/(m K) is 0.15 / 0.038 = 3.95 m2K/W, which is R-22.4 in the imperial units US products are labeled with.
    2. The air films count as layers too. A thin film of still air clings to each face, worth 0.13 inside and 0.04 outside, R-0.97 together. Building codes quote U-values that include them, which is why the calculator asks whether to count them rather than deciding for you.
    3. Resistances add up in series. Brick plus wool plus films gives 4.61 m2K/W. This is the only step where the arithmetic is genuinely easy, and it is the reason a thin layer of good insulation beats a thick layer of bad.
    4. The U-value is one divided by that total. 1 / 4.61 = 0.217 W/(m2 K). Turn it over again whenever someone quotes you a U and you want an R.
    5. The heat flow is U times area times the temperature difference. 0.217 x 30 x 26 = 169.2 W, and that is the figure your heating has to replace every second of every hour the weather stays like that.

    What each extra centimeter buys, and where it stops paying

    The same brick wall, the same weather, mineral wool added in five thicknesses. Every row came out of the calculator itself.

    Mineral wool added Total R Heat flow Saved Gain over the row above
    NothingR-3.81,175.6 W--
    5 cmR-11.2394.1 W66.5 %781.5 W
    10 cmR-18.7236.7 W79.9 %157.4 W
    15 cmR-26.2169.2 W85.6 %67.6 W
    20 cmR-33.7131.6 W88.8 %37.6 W
    30 cmR-48.691.1 W92.2 %40.5 W, over a 10 cm step

    Read the last column downward and the whole economics of insulation is right there. The first five centimeters kill 781.5 W. The second five kill 157.4 W, a fifth as much for the same material and the same labor. By the step from 15 to 20 cm you are buying 37.6 W. Nothing about that is a diminishing return in the material: resistances add in a straight line, but the heat flow is one divided by their sum, and one over a growing number flattens fast. It is the reason the argument is always about the first layer and never about the last.

    R-value per inch, and why one word covers two numbers

    A US product is labeled with an R-value in ft2 °F h/BTU, and the rest of the world quotes conductivity in W/(m K) or resistance in m2K/W. One SI unit of resistance is 5.678 imperial ones, exactly, so nothing here is a rule of thumb.

    Material W/(m K) R per inch What that looks like on site
    PUR or PIR foam0.023R-6.27The thin option, for when depth is the constraint
    XPS foam board0.033R-4.37Below grade and under slabs, because it resists water
    EPS foam board0.035R-4.12The white bead board sold as rigid foam sheathing
    Mineral wool0.038R-3.80Slightly worse per inch than foam, and it does not burn
    Blown cellulose0.040R-3.61Attics, where depth is free and access is awkward
    Fiberglass batt0.044R-3.28Six inches of it is the R-19 batt sold by the roll
    Aerated concrete block0.120R-1.20Structure and modest insulation from one material
    Softwood0.130R-1.11The stud that bridges your insulation, in one number
    Solid brick0.770R-0.19Half a meter of it is worth about half an inch of PUR foam
    Concrete1.700R-0.08Structural, and thermally close to a hole in the wall
    Steel50R-0.003A lintel or a balcony slab, carrying heat straight out

    Six surfaces, and what the calculator says about each

    A single pane of glass, 4 mm, 2 m2, 20 °C against -5. Heat flow 287.4 W, total R-1.0.
    Of that resistance, 97.7 percent is the two films of air on the faces. The glass itself contributes 0.004 m2K/W, which rounds to nothing. A window insulates because of the air trapped near it and, in a double unit, the gas between the panes. Never because of the glass.
    A 1 mm steel panel, 1 m2, 20 K across it. Heat flow 117.6 W, total R-1.0.
    The steel's own resistance is 0.00002 m2K/W. Take the films away and the flow goes to 1,000,000 W, which is the calculator telling you that a bare metal sheet is not a wall. Any steel that crosses your insulation is a hole in it.
    A 20 cm bare concrete wall, 20 m2, 21 °C against -5. Heat flow 1,807.8 W, total R-1.6.
    Nearly two kilowatts through one wall, which is a fan heater running permanently. Concrete is structure, not insulation, and every argument about its thermal mass is about when the heat arrives, not how much of it leaves.
    A 25 cm aerated concrete block wall, 30 m2, 26 K. Heat flow 346.2 W, total R-12.8.
    Eight times the total resistance of the concrete wall above, and nearly eighteen times the resistance of the concrete itself, from a material that still carries the roof. It sits right at the R-13 that milder climate zones ask of a wall assembly, and short of the R-20 the cold ones want.
    A 400 sq ft ceiling with 6 in of fiberglass batt, 70 against 10 °F. Heat flow 340.9 W, which is 1,163 BTU/h, total R-20.6.
    This is the standard R-19 batt with the air films added on top of it. Fine for a wall in a cold zone, thin for a ceiling, where the same codes ask for R-38 to R-60 because heat leaves upward and the depth is free.
    An attic with 40 cm of blown cellulose, 60 m2, 20 against -10 °C. Heat flow 177.0 W, total R-57.7.
    Over half again the area of the ceiling above, and half the heat loss. Depth in an attic costs almost nothing beyond the material, which is why this is the one place where R-50 and beyond is routine rather than extravagant.

    Seven answers about walls that lose more than they should

    Should I include the surface air films or not?
    Include them whenever you are comparing against a code figure, a product U-value or another assembly, because that is how those numbers are defined. Leave them out when you want the resistance of the material on its own. On a well-insulated wall the difference is small, 0.233 against 0.217 W/(m2 K) on 15 cm of EPS. On a single pane it is the whole answer.
    How much insulation is enough?
    US codes commonly ask for R-13 to R-21 in a wall and R-38 to R-60 in an attic, depending on climate zone. The table above shows what that means in centimeters for each material: R-21 is about 14 cm of mineral wool or 8.5 cm of PUR. Past those levels the wall stops being the thing losing your heat, and windows, air leakage and ventilation take over.
    Why is my real heating bill worse than this calculation?
    Because a house is not one flat layer. Studs, joists, lintels and fixings bridge the insulation and add 5 to 15 percent on a framed wall. Windows and doors have their own, much worse, U-values. Air leakage carries heat out without touching a wall at all, and in a poorly sealed house it can rival everything conduction does. This calculator answers one surface at a time, exactly.
    Does an air gap in the wall insulate?
    A thin one does. Still air has a conductivity of 0.026 W/(m K), better than any solid insulation, but it only stays still up to about 20 mm in a vertical gap. Past that it starts to circulate, and convection carries heat across faster than conduction ever would, so the resistance stops climbing with width. That is why a cavity gets filled rather than widened, and why a double glazing unit has a gap of 12 to 16 mm rather than 10 cm.
    Is a thermal mass wall a substitute for insulation?
    No, and the two answer different questions. Conductivity says how fast heat crosses; heat capacity says how much the material holds on the way. A heavy wall delays and smooths the swing, which is genuinely useful in a climate with hot days and cold nights, but over a long cold spell the average loss is set by the R-value alone. Twenty centimeters of concrete stores a lot and still leaks 1,807.8 W in the case above.
    Why does wet insulation stop working?
    Because water conducts at 0.6 W/(m K) against still air's 0.026, more than twenty times worse, and insulation is mostly trapped air. Displace even a fraction of that air with water and the conductivity of the assembly climbs toward the water's. It is also why the figures here are quoted as dry values, and why the detail that keeps insulation dry matters more than the last centimeter of thickness.
    Can I convert my answer straight into money?
    Multiply the watts by the hours to get watt-hours, then divide by a thousand for kilowatt-hours, and only then apply a price and the efficiency of whatever produces the heat. The brick wall above saves 24.2 kWh a day while it is 26 K colder outside than in. It saves nothing on a mild day, which is why annual savings are estimated from degree-days rather than from a single cold snap.

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    Calculator verified by the LiczGrupa.pl team

    Content, formulas and results have been reviewed for accuracy and relevance by our team of specialists.

    Patryk Matyjasik

    Reviewed by: Patryk Matyjasik