Acceleration Formula Calculator - a = (v - v0) / t

    How hard was that pull, in numbers? Enter three of the four quantities of straight-line motion and read the fourth, with the rate in m/s2, ft/s2 and g, and the distance alongside it.

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    Enter data for calculations

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    Used for everything you type and read back

    The speed before anything changes

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    A speed change, a clock, and the four numbers that follow

    Straight-line motion at a steady rate has exactly four quantities in play: the speed you start at, the speed you end at, how long it takes and how far you travel. Give this calculator any three of them and it returns the fourth, plus the acceleration in m/s², in ft/s² and as a fraction of g. A car going from 0 to 60 mph in 5.4 s comes out at 4.97 m/s², which is 16.30 ft/s² or 0.51 g, and it covers 237.6 ft doing it. Speeds go in as mph, km/h, m/s or ft/s, and the answer leads with whichever unit you chose.

    This is the physics definition of acceleration, the rate a speed changes at. If what you actually want is how quickly a specific car gets to 60 from its power and weight, that is a different question with a different tool, linked at the bottom.

    Pick the unknown first, then fill the boxes that stay

    The form rearranges itself around your choice, so you never see a field the selected mode does not use.

    1. 1
      Choose what you are solving for. Acceleration, final speed, time or distance. This decides which three fields remain below.
    2. 2
      Set the speed unit. Everything you type and everything you read back uses it. US readers usually want mph, a lab report usually wants m/s.
    3. 3
      Enter the starting speed. Pulling away from rest is 0. Braking from a cruise is whatever the speedometer read before you touched the pedal.
    4. 4
      Enter the two remaining knowns. A final speed, a time, or an acceleration with its own unit. A minus sign on the acceleration means slowing down, and the sign has to agree with the direction the speed moves.
    5. 5
      Read the answer and the three tiles under it. Time taken, distance covered and speed gained per second come with every mode, so one calculation fills in the whole picture.

    Four modes, and which one your question belongs to

    Most questions about motion are one of these four sentences with a different word missing. The right-hand column is the sanity check on your own input before you trust the output.

    Mode You already know Typical question Watch for
    Acceleration both speeds and the time How hard did that pull actually feel? a stopwatch that starts late flatters the result
    Final speed start speed, acceleration, time Where do I end up after eight seconds of this? braking can reach a standstill before the clock runs out
    Time both speeds and the acceleration How many seconds does that merge need? the sign of the acceleration must match the direction of the change
    Distance both speeds and the acceleration How much road does it eat while that happens? this is the physics distance, with no reaction time added

    The distance mode is the one people most often mistake for a stopping-distance tool. It answers both directions, so 30 to 60 mph at 2 m/s² gives 443 ft of road used while speeding up, and 56 mph down to a standstill at 8 m/s² gives 128 ft of pure braking. Neither figure includes the second or so you spend reacting before anything happens.

    The four relations, written out with real numbers

    Everything above comes from two relations and their rearrangements: v = v0 + a × t and v² = v0² + 2 × a × s. Speeds go into both in meters per second, which is why the calculator converts your entry before it does anything else. One mph is 0.44704 m/s exactly, and one km/h is 0.2778 m/s.

    A hot hatch, 0 to 60 mph in 5.4 s. 60 mph is 26.82 m/s, so a = 26.82 / 5.4.
    Result: 4.97 m/s², 0.51 g, and 237.6 ft of road used.
    Emergency braking from 70 mph at 7 m/s². 70 mph is 31.29 m/s, so t = 31.29 / 7.
    Result: 4.47 s and 229.4 ft, before any reaction time.
    A freight train pulling away at 0.4 m/s² for 60 s. v = 0 + 0.4 × 60.
    Result: 24 m/s, which is 53.7 mph, after 2,362 ft of track.
    A cyclist easing from 18 to 9 mph over 4 s. The speeds are 8.05 and 4.02 m/s.
    Result: -1.01 m/s², a gentle 0.10 g, over 79.2 ft.
    An elevator starting upward at 1.2 m/s² for 1.5 s. v = 1.2 × 1.5.
    Result: 1.8 m/s, 0.12 g of extra push into the floor, over 4.4 ft.

    Where this arithmetic usually slips

    Mixing a speed in mph with an acceleration in m/s² by hand. Wrong by a factor of 2.24 every time. Set the two unit selectors and let the conversion happen where it cannot be forgotten.
    Typing a positive acceleration for a slowdown. The calculator refuses it rather than quietly flipping the sign, because a positive value with a falling speed describes something that does not happen.
    Running the clock past a standstill. Ten seconds of braking at 5 m/s² from 31 mph is not ten seconds of motion: the object stops after 2.77 s and travels 63 ft, not the 227 ft a blind average would suggest.
    Reading the distance as a stopping distance. Reaction time is not in it. At 70 mph, one second of thinking adds 103 ft on its own, roughly 45 percent again on top of the braking itself.
    Assuming the rate held steady. Real engines and real tires do not deliver a constant figure, so treat any single number as the average across the window you measured.

    Reference values, from a train to a launch track

    The result places your own figure inside this ladder, so you can see at a glance whether a stopwatch reading is plausible. Everything a road vehicle does, hard braking included, sits in the top five rows.

    Situation m/s² ft/s² g
    Train pulling out of a station0.752.460.08
    City bus getting up to speed1.203.940.12
    Family car, relaxed start2.006.560.20
    Sports car, 0 to 60 mph in 5.4 s4.9716.300.51
    Hard braking on dry asphalt9.0029.530.92
    Free fall at the surface9.8132.171.00
    Carrier catapult launch35.80117.453.65
    Roller coaster launch, top end50.00164.045.10

    Loose ends worth naming

    Is deceleration a different thing from acceleration?
    No. It is the same quantity with a minus sign, which is why one field covers both. The result labels it braking when the value is negative, and the g figure is quoted without the sign because a passenger feels the strength, not the direction.
    Why does 0 to 60 mph in 5.4 s come out at only half a g?
    Because 1 g is 21.9 mph gained every second, and that run gains 11.1 mph per second. A full g from rest would reach 60 mph in 2.7 s, which is supercar territory. Half a g already pins you into the seat noticeably.
    Can I use this for the distance my car needs to stop?
    For the braking part, yes: enter your speed, a final speed of zero and a negative acceleration. Dry asphalt with good tires is about -8 to -9 m/s², wet is nearer -5. What it will not add is reaction time, which at 60 mph costs 88 ft for every second before you touch the pedal.
    What if the rate was not constant?
    Then what comes back is the average over the interval you gave, and it is still the honest answer to "how fast did the speed change on the whole". Split a run into segments and calculate each one if you need the shape of it rather than the summary.
    Why does the calculator refuse some perfectly reasonable-looking entries?
    Because a rising speed with a negative acceleration, or a falling speed with a positive one, has no solution in constant-rate motion. Older tools take the absolute value and hand back a number anyway. That number describes nothing, so this one names the clash and asks you to flip the sign.
    How much does an acceleration change what I weigh on a scale?
    In a straight line it changes the push into your seat, not the reading of a bathroom scale under your feet unless the motion is vertical. In an elevator accelerating upward at 1.2 m/s², a scale reads about 12 percent more than standing still, and the same amount less on the way down.

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